HCP crystal is made of A ions and B ions are arranged in 2/3rd of octahedral voids. The formula of the unit cell is?
Dear Student,
Please find below the solution to the asked query:
HCP structure has 6 atoms present per unit cell.
A occupies HCP structure, therefore A= 6
Also there are 6 octahedral voids in HCP arrangement.
according to the question,
B occupies 2/3of voids
so 2/3 *6 = 4
thus the simplest ratio is A:B = 6:4
A:B = 3:2
Thus the formula is A3B2
Please find below the solution to the asked query:
HCP structure has 6 atoms present per unit cell.
A occupies HCP structure, therefore A= 6
Also there are 6 octahedral voids in HCP arrangement.
according to the question,
B occupies 2/3of voids
so 2/3 *6 = 4
thus the simplest ratio is A:B = 6:4
A:B = 3:2
Thus the formula is A3B2