he diameters of three concentric circles are in the ratio 1:2:3. the sum there circumference is 264 find the area enclosed between second and third circle.

let the radius be d/2,d1/2,d2/2

pid+pid1+pid2=264

pi(d+d1+d2)=264

d+d1+d2=264*7/22

d+d1+d2=84

therefore d:d1:d2=1:2:3

let the ratio be x therefore d+d1+d2=1x+2x+3x

6x=84

x=14

Therefore the diametres are 14,28,42

So the difference in area between circle 3 and 2=pi(d2/2)^2-pi(d1/2)^2

therefore pi{(21)^2 - (14)^2}=pi(245)

22/7*245=770

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