heat engine is given heat of 12 40 Joule if its efficiency is 45% what is the work done by Share with your friends Share 0 Anshu Agrawal answered this Solution: Efficiency of heat engine ( η ) = 45 % Work output ( W ) = ? Using the formula, Efficiency ( η ) = Work output ( W ) Heat input ( Q ) or 0.45 = W1240 ∴ W= 1240× 0.45 = 558J 0 View Full Answer