Help me to solve the question number 13

Dear student,

Given relation is:

Q.D.=(2/3)S.D.         .....(1)
6Q.D.=5M.D.            .....(2)
Standard deviation is 7.5 (given)
putting S.D. in (1)
Q.D.=(2/3)*(7.5)
Q.D.=5
Putting Q.D. in (2)
6*5=5* M.D.
M.D.=6

Quartile deviation=5 and mean deviation=6


Regards.

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