help please asap

help please asap The conductivity of a saturated solution of BaSO is 3.06 x 10-6 ohm-I cm-land its molar conductance is 1.53 ohm-I cm2 mol-l. The K of BaS04 will be : (1) 4 X 10-12 (3) 2.5 (2) 2.5 x 10-9

Dear student,

According to the relation ;  λm  = 1000× kM
                                        1.53 = 1000 × 3.06 × 10-6  / M 
                      Then ;  M  =  2 × 10-3 M  ( soubility of barium sulphate ) = S mol / L
 Now  as we know that The solubility product Ksp  =  S2  ( for Barium sulphate )
                                                                                = (  2 x 10-3 )2  =  4 x 10-6 (Mol/l )‚Äč2  ( option 4 )
Regards

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