Help please....i am sticking here


(2)Newton's second law states that the magnitude of force acting on the body can be given as time rate of change of its momentum .
Or , the acceleration of the body is directly proportional to the external forces acting on it. 

(3) the tension of the rope can be calculated by analysing the system
first take the two trolleys in a system . it is clearly noted that F=Ma46.5=(5.2+2)aa=6.5m/s2
Now the smaller trolley has free body diagram as 
So. 
Tcos 25-f'=m'aTcos25-5.1=2*6.5Tcos25=18.1NT=20.0N

Regards 

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