hep of rice is in the form of a cone whose diameter is 48 m and height 10 m. The heap is to be covered by a canvas to protect it from rain. find the cost of canvas required at Rs.. 70/ sq. m

Diameter ( d ) = 48 m
Radius ( r ) = 48/2 = 24 m
Height ( h ) = 10 m

So , length will be
l square = r square + h square
l square = 24 square + 10 square
l square = 676 m square
l. = √ 676 m square
l. = 26 m
Now we finds its CSA ,

= π r l
= 22/7 * 24 * 26 m square
= 1961.14286 m square

1 m square of canvas = Rs . 70
1961.14286 of canvas= Rs . 70 * 1961.14286
= Rs . 137280

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