Here, we got x = 0 by shifting all the terms except x, and got x = 2 by shifting - Maths - Application of Derivatives

Question

Here, we got x = 0 by shifting all the terms
except x, and got x = 2 by
shifting all terms except (2-x)
Fine till here
I want to ask what value we will get if we shift x
and (2-x) both to the RHS, i e , how we'll solve e
- 2 x   = 0 to get value of x ?!
Kindly solve

Shruti Tyagi · Accepted Answer

Dear student,

We have, dydx=0⇒xe-x2-x=0which means either xe-x=0 or 2-x=0⇒ xe-x=0 ⇒x×1ex=0              --[using a-m=1am]⇒x=0×ex⇒x=0when  2-x=0⇒x=2We cannot take both the terms x and 2-x to the right sides as they are two terms we can compare it with 0 one by one

Regards

Here, we got x = 0 by shifting all the terms except x, and got x = 2 by shifting all terms except (2-x). Fine till here. I want to ask what value we will get if we shift x and (2-x) both to the RHS, i.e., how we'll solve e - 2 x = 0 to get value of x ?! Kindly solve.

Here, we got x = 0 by shifting all the terms except x, and got x = 2 by shifting all terms except (2-x).
Fine till here.
I want to ask what value we will get if we shift x and (2-x) both to the RHS, i.e., how we'll solve $e^{- 2 x} = 0$ to get value of x ?!
Kindly solve.