Hey, can you solve this??

Dear Student,
Consider this figure for part (a)

 
Consider  AXMandCYMAM=MC (Since M is the midpoint of AC)YCM=XAM (Alternate interior angles)AX=CY (Given)AXMCYM (By SAScriteria)Hence Proved (a)
(b)Consider the figure for part (b)

Since AXMCYM1=2 (By CPCT)1+3=180° (Supplementary angles)2+3=180° ( 1=2)So, XYis a straight line (because angle at the centre is 180, so XMYdoent bend anywhere)Hence Proved (b)
Regards

 

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