Hey, can you solve this?? Share with your friends Share 1 Surabhi Grover answered this Dear Student, Consider this figure for part (a) Consider ∆AXM and∆CYMAM=MC (Since M is the midpoint of AC)∠YCM=∠XAM (Alternate interior angles)AX=CY (Given)⇒∆AXM≅∆CYM (By SAS criteria)Hence Proved (a) (b)Consider the figure for part (b) Since ∆AXM≅CYM⇒∠1=∠2 (By CPCT)∠1+∠3=180° (Supplementary angles)⇒∠2+∠3=180° ( ∠1=∠2)So, XY is a straight line (because angle at the centre is 180, so XMY doent bend anywhere)Hence Proved (b) Regards 0 View Full Answer