How to solve this simultaneous linear equation by elimination method?
$\frac{1}{2 (x + 2 y)} + \frac{5}{3 (3 x - 2 y)} = - \frac{3}{2} \frac{5}{4 (x + 2 y)} - \frac{3}{5 (3 x - 2 y)} = - \frac{61}{60}$

Question

How to solve this simultaneous linear equation by elimination
method?
1 2 ( x + 2 y ) + 5 3 ( 3 x – 2 y ) = – 3 2 5 4 ( x + 2
y ) – 3 5 ( 3 x – 2 y ) = – 61 60

Mohammed Faisal · Accepted Answer

How to solve this simultaneous linear equation by elimination method? 1 2 ( x + 2 y ) + 5 3 ( 3 x – 2 y ) = – 3 2 5 4 ( x + 2 y ) – 3 5 ( 3 x – 2 y ) = – 61 60

How to solve this simultaneous linear equation by elimination method?
$\frac{1}{2 (x + 2 y)} + \frac{5}{3 (3 x - 2 y)} = - \frac{3}{2} \frac{5}{4 (x + 2 y)} - \frac{3}{5 (3 x - 2 y)} = - \frac{61}{60}$