Hi can someone please help me with this

Dear Student,

Let the smaller number be 'x'. So, the larger number = x + 7.
ATQ:
⇒ 6x + (x + 7) = 77
⇒ 6x + x + 7 = 77
⇒ 7x + 7 = 77
Subtracting 7 from both sides, we get
⇒ 7x + 7 - 7 = 77 - 7           
⇒ 7x = 70
Dividing both sides by 7, we get
7x7 = 707                         
 x = 10
Thus, the smaller number = x = 10, and the larger number = x + 7 = 10 + 7 = 17.
The two required numbers are 10 and 17.

Regards!

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