How can we construct a parallelogram ABCD in which AB = 6.5 cm , AC = 3.4 cm and the altitude AL from A is 2.5 cm .
Please explain the steps of construction.
Here is the answer to your question.
Follow the given steps to construct the parallelogram ABCD.
Step 1. Draw AB = 6.5 cm.
Step 2. At A, draw AE ⊥ AB. With A as centre and radius 2.5 cm, mark an arc which intersects AE in F.
Step 3. Draw a line parallel to AB and passing through F.
Step 4. With A as centre and radius 3.4 cm, mark an arc which intersects the line parallel to AB in C.
Step 5. With C as centre and radius 6.5 cm, mark an arc which intersects the line CF in D. (Opposite sides of parallelogram are equal)
Step 6. Join BC and DA.
Thus, ABCD is the required parallelogram.