How can we construct a parallelogram ABCD in which AB = 6.5 cm , AC = 3.4 cm and the altitude AL from A is 2.5 cm .
Please explain the steps of construction.
Hi!
Here is the answer to your question.
Follow the given steps to construct the parallelogram ABCD.
Step 1. Draw AB = 6.5 cm.
Step 2. At A, draw AE ⊥ AB. With A as centre and radius 2.5 cm, mark an arc which intersects AE in F.
Step 3. Draw a line parallel to AB and passing through F.
Step 4. With A as centre and radius 3.4 cm, mark an arc which intersects the line parallel to AB in C.
Step 5. With C as centre and radius 6.5 cm, mark an arc which intersects the line CF in D. (Opposite sides of parallelogram are equal)
Step 6. Join BC and DA.
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Thus, ABCD is the required parallelogram.
Best Wishes!