how can we differentiate

x.(18-2x)

x.(18-2x) can be written as 18x-2x2

now,differentiating 18-2x2 w.r.t x

by using chain rule,

d/dx (18x) - d/dx (2x2)

18-4x ( xn on differentiation gives nxn-1)

so the answer is 18-4x........

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18-4x

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x.(18-2x) can be written as 18x-2x2

now differentiating with respect to x we get = 18-4x ................... as (differential of 18x is 18 and xn is nxn-1

I hope u got it

Thumbs up Plz..

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