how can we use this formula..after converting natural log into log we multiply 2.303 we havent put value of R and F also?? how come this formula its no where in book
Dear student,
The factor 0.0591 we get after putting the values of R and F and we have considered the value n= 1 here in this case because no. of electrons taking part in the reaction is 1
We know ,R = 8.314 J mol-1 K-1 ;F = 96500 C ; T = 298 K (usually)
So 2.303 *R*T/n*F = (2.303*8.314*298)/96500*1 = 0.0591 V
Regards
The factor 0.0591 we get after putting the values of R and F and we have considered the value n= 1 here in this case because no. of electrons taking part in the reaction is 1
We know ,R = 8.314 J mol-1 K-1 ;F = 96500 C ; T = 298 K (usually)
So 2.303 *R*T/n*F = (2.303*8.314*298)/96500*1 = 0.0591 V
Regards