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how come the value of the (a+c)^2-4ac = (a-c)^2

We have,

(a + c)2 - 4ac = a2 + c2 + 2ac - 4ac

= a2 + c2 - 2ac

= (a- c)2 [using: (x- y)2 = x2 + y2 - 2xy]

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 this is because, (a+c)^2-4ac=(a^2+b^2+2ac)-4ac

                                                    =a^2+b^2-2ac

                                                    =(a-b)^2

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