How do I solve this formula Share with your friends Share 0 Guhan Mersal answered this Here is proof 1 View Full Answer Sudhashu Ranjan answered this No sir 0 Guhan Mersal answered this Please find this answer 0 Navin Saxena answered this a+b=m, a-b=n, so LHS=m^3 - n^3=(m-n)*(m^2+n^2+mn)= Putting value of m&n in above we get= (2b)* (2a^2+2b^2+a^2-b^2) =2b*(3a^2+b^2) =2(b^3+3a^2b) =RHS 0 Sachi answered this (a + b)3 = a3 + b3 + 3ab (a + b) (a - b)3 = a3 - b3 - 3ab (a - b) (a + b)3 + (a - b)3 = 2(b3 + 3a2b) 0
