How do we get this?? It is of Example:4 of Ch.12 ( Alternative Method)

How do we get this?? It is of Example:4 of Ch.12 ( Alternative Method) AREAS RELATEn TO CIRCLES Alternative Solution : Total area = Area of sector OAB + Area of sector ODC + Area of A OAD + Area of A OBC 233 90 22 90 — x — x 28 x 56 + — 360 7 22 7 8 x 56 + —x 56x 56+—x56x56 m 4 4 22 22 = —x28x56 — + —+2+2 m 4 7 x 56 (22 +22+ 14+ 14)m2 7 = 56 x 72 = 4032 m: Example 5 : Find the area of the shaded region in Fig. 12.16, where ABCD is a square of side 14 cm. Solution : Area of square ABCD = 14 x 14 cm2 = 196 cm2 00 00 Fig. 12.16 so, Therefore, Diameter of each circle = radius of each circle —cm area of one circle rtr2 — 154 4 area of the four circles 14 —cm 7 cm 7 22 7 7 — — x —x —cm 77 2 4 —cm2 = 154 cm 2