how is the mechanical advantage of a hydraulic lift A2/A1, where A2 and A1 are the area of cross section of the larger and smaller piston respectively ?

Area of small cross-section = A1

Force exerted on it = F1

Pressure transmitted, 

Area of larger piston = A2

Upward force on the piston = P × A2

Force supported by the large piston, F2 = PA2

F2 

Since A2 is greater than A1, force F2 on the larger piston will also be much larger than the force F1 applied on the smaller piston.

Thus the mechanical advantage is the ratio of the weight lifted by the machine to the force applied to lift it, which is equal to the ratio of cross sections A2 and A1.

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