How m1=(1+?2)x and
m2=(1-?2)x
Explain?

How m1=(1+?2)x and m2=(1-?2)x Explain? (iii) — + 4y2 O 'x —yÅ3x— 4y) O and 3.r—4yzO aretheirscparate• It's auxilliary equation is — 2m — I —O Which is quadratic equation in m. hexeiti. roots m and m: which are slOFs of tyr Iirxs Of x: • 20 ' — • O. Clearly, Equations oflines are.v•• m andy 2s. y -(1-di)x = O and — ay)€ßx 0

Please find below the solution to the asked query:

We have :  m2 - 2 m - 1 = 0 

And we know quadratic formula : x  = -b ±b2- 4 a c2 a , Here a = 1 , b = - 2 and c = - 1 , So

m = -  - 2  ±  - 2 2- 4 × 1×  - 1 2 × 1 = 2 ± 4 + 42= 2 ± 82= 2 ±222= 2  1 ±22= 1 ±2

Therefore,

m1 = 1 + 2 and m2 = 1 - 2

Hope this information will clear your doubts about topic.
 

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