# how many 5 digit even numbers can be formed from the digits 0, 1,2,3 and 4, if repetition of digits is not allowed?

We can make 72 5-digit even numbers from 0,1,2,3,4 if no digit is repeated.

Explanation :

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There are total 5 places. At unit place we can have 3 possibilities 2,4 & 0 to make number even.

when 1 digit is selected at unit place then remaining place will have 4,3,2 and 1 possibilities only as we can not repeat the digits.

Regards,

So your answer required will be multiplication of this possibilities. hence answer is $4\times 3\times 2\times 1\times 3=72$

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