how many atoms are present in 0.25 mole of so​​3?

1 mole of so3 contains atoms= 6.022*10^23 atoms

 therefore, 0.25 moles contains atoms = 6.022*10^23 * 0.25 atoms

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First we'll find the no. of molecules in the given no of moles, 1 mole of SO3 = NA(Avogadro No) molecules 0.25 moles = (1/4)*NA molecules To find No. Of atoms, we'll multiply no. Of molecules by its atomicity. No. Of atoms = 4*(1/4)*NA = NA = 6.022*10^23
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