How many different words can be formed of the letters of the word 'MALENKOV ' so that:

1) No two vowels are together.

2) The vowels may occupy odd places

For the second part of the question the answer is :

4P3 x 5P4 = 2880 ways 

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First part: we shall arrange the consonants that is m l n k v = 5! Second part: Now we shall insert vowels in between like this _m_l_n_k_v_ 6 places and we have to put three vowels between them, So we first pick 3 place out of these 6 => =6!3!(6−3)!6363 = 2020 Third part: Arrange the 3 vowels  that is 3!3 ways 5!∗20∗3!=14400
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First part: we shall arrange the consonants that is m l n k v = 5! Second part: Now we shall insert vowels in between like this _m_l_n_k_v_ 6 places and we have to put three vowels between them, So we first pick 3 place out of these 6 => =6!/3!(6−3) Third part: Arrange the 3 vowels  that is 3!ways 5!∗20∗3!=14400
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Also Pls answer - when, The relative position of the vowels and consonants remains unaltered when, Vowels never occur together
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Abfh
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good
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