how many gram HCl is needed to react completely with 200g of 40%pure marble chips?

Chemical reaction between HCl and CaCO3‚Äč : 

CaCO+ 2HCl CaCl2 + CO2 + H2

2 mol of HCl (2×36.5 =71gm) react with 100% pure 1mol of CaCO3(100gm)if marble (CaCO3) is 40%pure then 28.4gm of HCl is needed to react. Thus, if  40% pure 100 gm CaCO3 require 28.4gm of HCl     40% pure 200 gm CaCO3 require = 200×28.4/100                                                          =56.8gm of HCl 

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