how many gram of HCL will be present in 150 ml of its 0.52 M solution Share with your friends Share 6 Avni answered this Molar mass of HCl = 36.5 g Molarity = 0.52 M Volume of solution = 150 mL Molarity = Given mass of HCl×1000Molar mass of HCl×Volume of solution 0.52 = Given mass of HCl×100036.5×1502.84 g 7 View Full Answer
