How many litres of C02 at STP will be formed when 100ml of 0.1 M H2SO4reacts with excess of Na2CO3?

c(H2SO4) = 0.1mol/L & v(H2SO4) = 100ml = 0.1L chemical equation is Na2CO3 + H2SO4 ------> Na2SO4 + H2O + CO2 so n(CO2) = n(H2SO4) .............[[from chemical equation]] = c(H2SO4) x v(H2SO4) .......[[using n = cv]] = 0.1 x 0.1 = 0.01mol then stp v(CO2) = 22.4 x n(CO2) = 0.224L at STP
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