# How many matrices of order 2x3 can be formed using the first two prime numbers?

Please find below the solution to the asked query:

$\mathrm{In}\mathrm{matrix}2\times 3,\mathrm{there}\mathrm{are}6\mathrm{places}\mathrm{and}\mathrm{every}\mathrm{place}\mathrm{can}\mathrm{be}\mathrm{filled}\mathrm{in}\mathrm{two}\mathrm{ways}.\left(\mathrm{i}.\mathrm{e}.\mathrm{two}\mathrm{prime}\mathrm{number}\right)\phantom{\rule{0ex}{0ex}}\mathrm{So},\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{matrices}={2}^{6}=\mathbf{64}$

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