How many minimum nitrogenous bases are present in the DNA cistron unit which transcribes mRNA for production of polypeptide of 150 amino acids? (1) 150 (2) 450 (3) 453 (4) 906
answer(4)
HOW????
Dear student,
Please find below the solution to the asked query
The correct option is (4).
Given,
Nnumber of amino acids in polypeptide chain = 150 amino acids.
Since each amino acid is coded by triplet codon (three bases), thus, the number of bases on mRNA strand coding for 150 amino acids = 150 x 3 = 450 bases.
Also one codon is terminator codon (made up of 3 bases) on mRNA that does not code for any amino acid.
Hence, total bases on mRNA = 450 + 3 = 453 bases.
Now since cistron is double stranded piece of DNA, thus each strand will have 453 bases and the minimum number of bases in cistron will be = 453 x 2 = 906.
Hope this information will clear your doubts about the minimum nitrogenous bases present in the DNA cistron unit which transcribes mRNA for production of polypeptide of 150 amino acids
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query
The correct option is (4).
Given,
Nnumber of amino acids in polypeptide chain = 150 amino acids.
Since each amino acid is coded by triplet codon (three bases), thus, the number of bases on mRNA strand coding for 150 amino acids = 150 x 3 = 450 bases.
Also one codon is terminator codon (made up of 3 bases) on mRNA that does not code for any amino acid.
Hence, total bases on mRNA = 450 + 3 = 453 bases.
Now since cistron is double stranded piece of DNA, thus each strand will have 453 bases and the minimum number of bases in cistron will be = 453 x 2 = 906.
Hope this information will clear your doubts about the minimum nitrogenous bases present in the DNA cistron unit which transcribes mRNA for production of polypeptide of 150 amino acids
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards