How many molecules are present in 710 g of chlorine gas (cl 2)? What will be the total number of atoms in it?

Dear student,

The molar mass of chlorine is 35.5 g. So the molar mass of Cl2 gas is 2 X 35.5 = 71 g. Now we know that there are 6.023 X 1023 particles in one mole of substance. Hence 

 71 g of Cl2 = 6.023 X 1023 molecules of Cl2 gas

 1 g of Cl2 = (6.023 X 1023) / 71 molecules of Cl2 gas

 So 710 g of Cl2 = (6.023 X 1023X 710) / 71 molecules of Cl2 gas

 = 6.023 X 1024 molecules of Cl2 gas

A mole of Cl2 gas contains 6.022×1024 molecules, but each molecule of chlorine gas contains two atoms. 

Total number of atoms present in Cl2 = (6.023 x 1024 x 2) = 12.046 x 10 24 atoms

Regards,

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Molecules=6×10^24 Atoms=12×10^24
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A mole contains?6.022???10 23 molecules, but each molecule of chlorine gas contains two atoms.
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