How many moles of magnesium are present in 0.478g of the element?

Molar mass of magnesium = 24.305 g/mol
Given mass of the element = 0.478 g

Number of moles in 0.478 g = 0.478/24.305
  = 0.019
  = 0.02

  • 2

its 0.478/12=0.0398moles

  • 0

Molecular mass of magnesium = 24.305 g/mol. 0.478 g/24.305 g/mol = .0197 mol

  • 1
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