How many moles of nitrogen are present in70 g of nitrogen?? explain..

1mole of nitrogen = 14 g (1 mole of an element= gram weight of that element)

Number of moles of nitrogen in 1g = 1/14 = 0.0714 moles.

1 g of nitrogen contains 0.0714 moles, therefore

70 g of nitrogen contains = 70 x 0.0714 = 5 moles

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1 mole of Nitrogen = 14 grams (1 mole of any element=the gram weight of that element)
=> 1/14 mole of Nitrogen = 1 gram
=> 1/14 mole * 70  = 1 gram  * 70 ( Multiplying R.H.S and L.H.S by the same no. does not make a difference, unitary method )

=> 5 moles = 70 gram

Hope this helps :)
Regards.

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