how many natural numbers less than 1000 can be formed with the digits 1,2,3,4and 5 if

1)no digits is repeated

2)repetition of digits is allowed

Dear Studentfriend Harmeet has given the correct answer for part 1.

Hi@Harmeet: Good effort! Keep posting!

Second part : When repetition of digits are allowed:

One digit number can be any of the five numbers 1, 2, 3, 4 or 5, so it can be done in five ways.

The no. of natural numbers with two digits: 

Unit place can be filled in any of the five ways.

Tens place can be filled in any of the five ways.

Thus, number of ways for two digit numbers = 5 × 5 = 25

Similarly, no. of natural numbers with three digits = 53 = 125

Hence total number of natural numbers = 5 + 25 + 125 = 155

  • 6
  • the no. of natural no. with one digit=5(1,2,3,4,5)
  • no. of numbers of two digit=20(5X4) eg.12,13,14......
  • no. of three digit numbers=60(5X4X3)eg.123,124,125.....
  • therfore total number of natural numbers=5+20+60=85

now just like this do second part :)

  • 4

_ _ _ 

3 places...

1st place- 6 ways of filling[including 0)

2nd place- 5 ways(including 0)

3               - 3 ways

 ..

there fore total ways = 6x5x3=90

  • -13

no man it is wrong the correct answere is 85  :)

  • -8
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