How many no (four digit) can be found using number 1,2,3,4 not exceeding 4321?
Dear Student,
Please find below the solution to the asked query:
We form four digits numbers from ( 1 , 2 , 3 , 4 ) , As :
Thousands place any one from { 1, 2, 3 } = 3 ways and Rest of the 3 places ( All the 4 ( 1 , 2 , 3 , 4 ) can be places ) = 43 = 64
Thus total = 3 64 = 192 numbers
ii) 4 at thousands place:
With either 1 or 2 at hundreds place = 1 2 4 4 = 32
With 3 at hundreds place & 1 at tens place = 1 1 1 4 = 4 [4311, 4312, 4313, 4314]
With 3 at hundreds place & 2 at tens place = 1 1 1 1 = 1 [4321]
Rest of the numbers are greater than 432 , So
Total numbers could be formed = 192 + 32 + 4 + 1 = 229 ( Ans )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
We form four digits numbers from ( 1 , 2 , 3 , 4 ) , As :
Thousands place any one from { 1, 2, 3 } = 3 ways and Rest of the 3 places ( All the 4 ( 1 , 2 , 3 , 4 ) can be places ) = 43 = 64
Thus total = 3 64 = 192 numbers
ii) 4 at thousands place:
With either 1 or 2 at hundreds place = 1 2 4 4 = 32
With 3 at hundreds place & 1 at tens place = 1 1 1 4 = 4 [4311, 4312, 4313, 4314]
With 3 at hundreds place & 2 at tens place = 1 1 1 1 = 1 [4321]
Rest of the numbers are greater than 432 , So
Total numbers could be formed = 192 + 32 + 4 + 1 = 229 ( Ans )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards