How many solutions are there to the equation x1 + x2 + x3 + x4 = 17, where x1, x2, x3, x4 are nonnegative integers? (A) 1140 (B) 1160 (C) 1040 (D) 1200 No Links
Dear Student,
Here given X1+X2+X3+X4=17
Consider the equation is A+B+C+D=X
Then the formula of finding numbers of possible non-negative integers solution is (X+4–1) C (4–1) [there are 4 numbers A, B, C, D]
SO The formula is 17+4-1 C 4–1=20C3 = 1140 (option A)
So 20C3 is the number of possible non-negative integers.
Regards