How many three digit numbers divisible by 12?

Answer is 75.
Ap- 108,120......996
an=996
a=108
d=12
an=a+(n-1)d
996=108+(n-1)12
888=(n-1)12
n-1=74
n=75
  • 10

The first three digit number which is divisible by 7 is 105 and last three digit number which is divisible by 7 is 994.

This is an A.P. in which a = 105, d = 7 and l = 994.

Let the number of terms be n . Then tn = 994.

nth term of A.P = tn = a + (n - 1)d.

⇒ 994 = 105 + (n -1)7.

⇒ 889 = 7(n-1)

⇒ n -1 = 127

∴ n = 128.

∴ There are128 three digit numbers which are divisible by 7.

 


































     
    • -4
    There are 75 three digit no. Divisible by 12
    • 5
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