How many types of zygotic combinations are possible between a cross Aa BB Cc Dd x AA bb Cc DD?
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Dear student
Please refer the solution below for the said query
AaBBCcDd X AAbbCcDD
The number of possible gamates = 2n, where n is number of heterozygous pairs of genes.
In above cross the number of heterozygous pairs of genes in first parent = 3, therefore possible gamates = 23 = 8
The number of heterozygous pairs of genes in second parent = 1, therefore possible gamates = 21 = 2
When 8 combinations are crossed with 2 combination, the number of zygotic combinations = 8 x 2 = 16.
Hope this information clears your doubt about the topic.
Regards
Please refer the solution below for the said query
AaBBCcDd X AAbbCcDD
The number of possible gamates = 2n, where n is number of heterozygous pairs of genes.
In above cross the number of heterozygous pairs of genes in first parent = 3, therefore possible gamates = 23 = 8
The number of heterozygous pairs of genes in second parent = 1, therefore possible gamates = 21 = 2
When 8 combinations are crossed with 2 combination, the number of zygotic combinations = 8 x 2 = 16.
Hope this information clears your doubt about the topic.
Regards