How much below the surface of earth dos the acceleration due to gravity become 1% of it's value at it's earth surface?
let g(d) be the acceleration due to gravity at a depth 'd',below earth surface.
g(d)=g(1-d/R)
where R = radius of earth.= 6371 km
according to question,
9.8/100 = 9.8(1-d/6371)
1/100 = 1-d/6371
6371-(6371/100) = d = 6307.29 km
6307.29 KM BELOW THE SURFACE OF EARTH ,THE ACCELERATION DUE TO GRAVITY WILL BE 1% OF ITS VALUE AT ITS EARTH SURFACE.