How much heat is required to raise the temperature of 0.15 kg of water from 20?C to 35?C?
(A) 22.5 kJ (B) 9.45 kJ
(C) 15.2 kJ (D) 20 kJ

Dear Student,
Heat required is given by:
 Q = m × c × Δ T ( Q, here symbolise that heat required in this case )

For water, the value of c is 4.186 J/g °C,
mass given= 0.15kg = 150g
Change in temperature= 15°C
So,
Q=150×4.186*15
= 9418.5J
= 9.45J

Regards