How much volume of 3.0 M H2SO4 is required for the preparation of 1.0 litre of 1.0 M solution?
To solve, we use the formula M1V1 = M2V2
M1 = 3.0 M
M2 = 1.0 M
V2 = 1.0 L
3.0 V1 = 1.0 1.0
0.33L of 3M sulphuric acid is required.
M1 = 3.0 M
M2 = 1.0 M
V2 = 1.0 L
3.0 V1 = 1.0 1.0
0.33L of 3M sulphuric acid is required.