How much work is required to carry a 6 micro coulomb charge from negative to positive terminal of a 9 V battery ?

Dear Student,

charge, q=6 μC=6×10-6 Cpotential difference, V=9 VWork done, W=qVW=6×10-6×9=54×10-6 J

  • 15
work done = charge x potential of battery
so,
work done = 6 micro couloumb x 9v
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