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Dear Student, Perimeter of the shaded region = circumference of circle with diameter 14 cm (r = 7 cm) + Perimeter of quadrant ABC (R = 21 cm) = 2 π \times r + (2 R + \frac{2 πR}{4}) = 2 \times \frac{22}{7} \times 7 + 2 \times 21 + \frac{22}{14} \times 21 = 44 + 42 + 33 = 119 cm A r e a o f t h e s h a d e d r e g i o n = A r e a o f quadrant ABC (R = 21 cm) - A r e a o f circle with diameter 14 cm (r = 7 cm) = \frac{1}{4} \times π \times R^{2} - {πr}^{2} = \frac{1}{4} \times \frac{22}{7} \times 21 \times 21 - \frac{22}{7} \times 7 \times 7 = \frac{11 \times 63}{2} - 154 = 192.5 {cm}^{2} Regard s

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