How to apply VBT and find the no. of unpaired electrons to find magnetic moment if there is more than one ligand in the complex? Q. The coordination number and magnetic moment of the complex [Cr(C2O4)2(NH3)2]- respectively is (1) 6, 3.87 BM (2) 4, 3.87 BM (3) 6, 3.46 BM (4) 4, 1.73 BM Share with your friends Share 0 Vartika Jain answered this Dear Student, The complex is [Cr(C2O4)2(NH3)2]-Oxidation number of Cr can be calculated as :x + 2(-2)+2(0)=-1or, x=-1+4=+3So, Electronic configuration of Cr3+ = [Ar] 3d3 4s0 4p0 4d0Now,C2O4 is a bidentate ligand so 1 C2O4 will bind from two sites. So,we have total 6 lone pairs to fill in these orbitals This makes hybridisation as d2sp3Now, here number of unpaired electrons (n) = 3Magnetic moment, s=n(n+2)=3(3+2)=3.87 BMHence, correct answer is (1) 2 View Full Answer
