How to convert n butane from ethyl iodide
Do it by wurtz reaction
2CH3-CH2-I +2 Na in the presence of dry ether gives CH3-CH2-CH2-CH3+ NaI
Ethyl iodide when added with sodium metal gives n butane as product and sodium iodide as bi product
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2CH3-CH2-I +2 Na in the presence of dry ether gives CH3-CH2-CH2-CH3+ NaI
Ethyl iodide when added with sodium metal gives n butane as product and sodium iodide as bi product
Vote if it's helpful