how to differentiate (sin2x) under root using product and qoutient rule.

Let f(x)=dsin2xdxlet u=sin2xthen we havedf(x)dx=dudud(sin2x)dxNow let 2x=t then we havedf(x)dx=dudud(sint)dxd2xdxdf(x)dx=12ucost 2Putting values we havedf(x)dx=1sin2xcos2xSo,df(x)dx=cos2xsin2x 

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