how to draw the given graph with given equation in the attachment

Dear student,

$$\begin{gathered} \raisebox{1ex}{$Q_2$}\!\left/ \!\raisebox{-1ex}{$2E$}\right.=1-\frac{3}{C+3} \\ \Rightarrow Q_2=2E(1-\frac{3}{C+3})=2E-\frac{6E}{C+3} \\ the equation can be compared with general equation \\ y=a-\frac{b}{x} \\ For C=0, Q_2=2E-\frac{6E}{3}=2E-2E=0 \\ For C=1, Q_2 =2E-\frac{6E}{1+3}=2E-\frac{6E}{4}=2E-\frac{3E}{2}=0.5E \\ For C=2, Q_2 =2E-\frac{6E}{2+3}=2E-\frac{6E}{5}= 0.8E \\ For C=3, Q_2 =2E-\frac{6E}{3+3}=2E-\frac{6E}{6}=E \\ For C=4, Q_2 =2E-\frac{6E}{4+3}=2E-\frac{6E}{7}=1.14E \\ For C=5, Q_2 =2E-\frac{6E}{5+3}=2E-\frac{6E}{8}=1.25E \end{gathered}$$
So, by ths way, we can calculate the values of Q₂ for different values of C.
And we can draw the nature of the graph on a  graph paper and roughly the shape of the graph looks like this;


Regards,