hOW TO FIND ANTILOG AND LOG FROM THE LOG TABLE??

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Dear Student,

Let us understand log calculation, with the help of an example.

Suppose we have to find log of 3.352 x 10¹¹.

Taking log, 

log(3.352 x 10¹¹) = log (3.352) + log(10¹¹)

log(3.352 x 10¹¹) = log(3.352) + 11 log(10)

log(3.352 x 10¹¹) = log(3.352) + 11

To find log(3.352), we will look for the value in 33^th row, 5^th column, which is 5250. To this we add the mean difference of the 2^nd column, in the same row, in the log table.

5250 + 3 = 5253.

Now, log(3.352) = 0.5253

So, log(3.352 x 10¹¹) = 11+0.5253 = 11.5253

Let us now, take antilog of 11.5253.

The digits before the decimal becomes the mantissa.

antilog(11.5253) = antilog(0.5253) x 10¹¹

To find the value of antilog(0.5253), we will look for the value in 0.52^th row, 5^th column, which is 3350. To this value add the mean difference of 3^rd column, in the same row, in the antilog table.

3350+2=3352

Therefore, antilog(0.5253)=3.352.

So, antilog(11.5253) = 3.352 x 10¹¹.

Hope, its clear now.

Enjoy learning!!