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How to find dy/dx when y=cos-1[2cosx+3sinx]/root13 ??????

$y = \cos^{- 1} (\frac{2 \cos x + 3 \sin x}{\sqrt{13}}) y = \cos^{- 1} (\frac{2}{\sqrt{13}} \cos x + \frac{3}{\sqrt{13}} \sin x) = L e t \cos θ = \frac{2}{\sqrt{13}} \Rightarrow \sin θ = \sqrt{1 - \cos^{2} θ} = \frac{3}{\sqrt{13}} y = \cos^{- 1} (\cos θ \cos x - \sin θ \sin x) = \cos^{- 1} (\cos (θ + x)) = θ + x \frac{d y}{d x} = 1$

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