How to find the middle term in the expansion of (1-(1/x))^n(1-x)^n - Maths - Binomial Theorem

Question

How to find the middle term in the expansion of
(1-(1/x))^n(1-x)^n

Deleted · Answer

(1-1/x)n (1-x)n is equivalent to :
(-1)n
[x1/2-1/(x1/2)]2n
The required middle term should be (-1)n
2nCn (-1)n (Note that the
x1/2 and x-1/2 is cancelled and
(-1)n remains )
Alternate would be to expand both the binomials and calculate
the coefficient independent of x
which is , nC02
+nC12 +
+nCn2 =
2nCn