How to get the find the phenotypic ratio and Genotypic ratio for this?
Dear Student,
Parents AaBbCc (Mother) x aaBbcc (Father)
No of Gametes 23 (8) 21 (2)
Gametes ABC, ABc, AbC, Abc, aBc and abc
aBC, aBc, abC, abc
Number of gametes = 2n (number of heterozygous pairs)
F1 will be
Now, it is given AaBbCc - Dark
aaBbcc - Almost White
AaBBCc - More Dark
aabbcc - White.
Using the above cross and given phenotypes rest can also be easily computed.
If you face any problem do get back to us.
Hope this information will clear your doubts about the topic.
For more queries just ask in a separate thread here on the forum and our experts will try to help you out as soon as possible.
Regards
Parents AaBbCc (Mother) x aaBbcc (Father)
No of Gametes 23 (8) 21 (2)
Gametes ABC, ABc, AbC, Abc, aBc and abc
aBC, aBc, abC, abc
Number of gametes = 2n (number of heterozygous pairs)
F1 will be
aBc | abc | |
ABC | AaBBCc | AaBbCc |
ABc | AaBBcc | AaBbcc |
AbC | AaBbCc | AabbCc |
Abc | Aabbcc | Aabbcc |
aBC | aaBBCc | aaBbCc |
aBc | aaBBcc | aaBbcc |
abC | aaBbCc | aabbCc |
abc | aaBbcc | aabbcc |
Now, it is given AaBbCc - Dark
aaBbcc - Almost White
AaBBCc - More Dark
aabbcc - White.
Using the above cross and given phenotypes rest can also be easily computed.
If you face any problem do get back to us.
Hope this information will clear your doubts about the topic.
For more queries just ask in a separate thread here on the forum and our experts will try to help you out as soon as possible.
Regards