how to integrate sin2(2x+5)...and sin4xcos2x​x

We have,sin22x+5dx=122sin22x+5dx=121-cos22x+5dx=121-cos4x+10dx=12dx-12cos4x+10dx=x2-12×sin4x+104+C    Where, C is integral constant=x2-18sin4x+10+CNote: kindly check the exponent of cosx in second integration.

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