How to prove : 27^log2 =8^log3

Taking log on both sides'
log 27^log 2= log 8^{log 3}
Therefore log 2 * log 27 = log 3 *  log 8                    (As log a^b = b*log a)
                 log 2 * log 3³ = log 3 * log 2³
                 log 2 * 3 * log 3 = log 3 * 3 * log 2
PROVED